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169=2x^2+14x+49
We move all terms to the left:
169-(2x^2+14x+49)=0
We get rid of parentheses
-2x^2-14x-49+169=0
We add all the numbers together, and all the variables
-2x^2-14x+120=0
a = -2; b = -14; c = +120;
Δ = b2-4ac
Δ = -142-4·(-2)·120
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-34}{2*-2}=\frac{-20}{-4} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+34}{2*-2}=\frac{48}{-4} =-12 $
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